THEORY BREAK-THRU TRUE TENSION-ONLY | FAKE TENSION-ONLY | ZERO-COMPRESSION TENSION-ONLY |
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TRUE REPRESENTATION | MISREPRESENTATION | |
USP, 1976 (UTP,1970) | STAAD III | ALL OTHERS |
ELEMENT BEAM,TRUSS & ONE-Way | ELEMENT BEAM, TRUSS (BEAM & TRUSS:NO/YES ?) | ELEMENT BEAM & TRUSS YES/NO ? |
PRECISE RESULT with Euler Critical Buckling Compression | NO | NO ? |
Option for Zero Compression: YES (also as a tool to check lower tech competitors' programs) | NO | N/A |
Correct Result for Deflection Control Structures: Radio telescope, antenna dish | NO | NO |
All member loads (USP accepts member loads on ELEM TRUSS in addition to self-weight load generation in any direction to be powerful.) | YES/NO ? | |
(Most of them 3-D structures) NO such example except fake examples |
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If provided, YES but hard since it has NO ready Global Coordinate Output. | YES (some HARD ?) | |
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For a joint to which Zero Compression Members link,
you can tally and sum up at this joint all forces that are (input to it and) output from all elements in a given, say; Y-direction.
Frequently forces that are associated with the Zero Compression Members, unlike those by U S P, are NOT listed in the output. If so, the Joint is NOT in eqilibrium due to the fact the external loads on the members are not accounted for. The equilibrium forces from the Members are by simple statically determinate end reaction. (normally 50 % of member loads; see (5) of Column II below.) You can hand calculate to check easily. | |
All in ONE INPUT and ONE OUTPUT (Unlimited load cases including temperature variations and lack-of-fit-in-length load cases.) | NO. (LOAD COMBINATIONS ?)
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DONE internally by computer
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NO PROBLEM | : For the given loading condition, the loads (dead load, snow/ice load, wind load and/or live load) on those deleted members have not been accounted for during the above manual input-output cycles. | Problem exists ? You as a user can find out byJoint Static Equilibrium. |
with PRECISE RESULTS | INCORRECT RESULTS THERE if above is true?
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Another loading case: ONE additinal simple load case within the same input set. | Another loading case: a big manual input-studyoutput-reinput CYCLES like the one previously | ONE additional load case within the same input set. (Frequently total load cases are limited.) |
: 1 1.4 2 1.7
(Say; 1.4 times Load Case 1 and 1.7 times Load Case 2) (O K and powerful) | LOAD COMBINATIONS: 1 1.4 2 1.7
This Command can NOT be used. For every combination, you must manually compute the load initially and treat them as one simple load case. An even bigger man-computer input-output cycles are needed because loads on deleted members in all likelihood must be accounted for. Otherwise, the results will NOT be useful in engineering. | NOT ALLOWED ? |
Oblique Planar Joints: As many as feaseable to stabilize the direction normal to each/every plane | NO. (This is Critical.) Fall Back:Introduce a small member for each planar joint. RESULT: Approximate analysis ? | YES/NO ? If NO, |
TRUE MEANINGFUL EXAMPLES provided with COMPLETE input and output that can be checked easily as mentioned above. | EXAMPLE PROBLEM NO. 4: An example to confuse the public. | |
A 3-D complex structure can not be pre-judged by practically any engineer. | ||
Conclusion: You as an end user can help police the bad apple by uncovering more of MISREPRESENTATION. |